Question

he American Heart Association is about to conduct an anti-smoking campaign and wants to know the fraction of Americans over 49 who smoke. Step 2 of 2 : Suppose a sample of 482 Americans over 49 is drawn. Of these people, 372 don't smoke. Using the data, construct the 90% confidence interval for the population proportion of Americans over 49 who smoke. Round your answers to three decimal places.

Answer 1

given data are :-

sample size (n ) = 482

number of persons who smoke = (482-372) = 110

sample proportion () = 110/482 = 0.2282

z critical value for 90% confidence level, both tailed test be:-

the 90% confidence interval for the population proportion of Americans over 49 who smoke is:-

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