Question

An advertising executive studying television viewing habits of married men and women during​ prime-time hours has determined that during prime​ time, husbands are watching television 63% of the time. When the husband is watching​ television, 56% of the time the wife is also watching. When the husband is not watching​ television, 23% of the time the wife is watching television. Complete parts a through c.

A.) A time during prime time is randomly selected. Determine the probability that the husband is not watching television and the wife is watching television.

B.) Determine the probability of the wife watching television during prime time.

C.) Given that the wife is watching​ television, determine the probability that the husband is also watching television.

Answer 1

(A)

	Husband watching	Husband not watching	Total
Wife watching	0.63X0.56=0.3528	0.37X0.23=0.0851	0.4379
Wife not watching	0.63 - 0.3528=0.2772	0.37-0.0851=0.2849	0.5621
Total	0.63	1 - 0.63 =0.37	1..

P(Husband not watching AND Wife watching) = 0.0851

(B)

P(Wife watching) = 0.4379

(C)

P(Husband watching/ wife watching) = P(Husband watching AND Wife watching)/ P(Wife watching)

                                                     = 0.3528/0.4379 = 0.8057