A sample of 35 luxury hotels in the US had an average room rate of $252.80 per night. Assume the population standard deviation is $41 per night. Calculate the standard error of the mean.
SOLUTION:
From given data,
A sample of 35 luxury hotels in the US had an average room rate of $252.80 per night. Assume the population standard deviation is $41 per night. Calculate the standard error of the mean.
standard deviation = s = 41
Sample size = n =35
Sample mean = = 252.80
The standard error of the mean
SE = s /
= 41 /
= 6.93
There fore ,
standard error of the mean = 6.93
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