Question

Please:

• You may NOT use Excel, SPSS, or any other statistical software to get your answers. You must show all of your by-hand computations for full credit.
• For each question, assume you’re using an alpha of .05, and a two-tailed test, to make your decision about whether to reject the null hypothesis.
• Conduct a Chi-squared test of independence on the data presented in Data Set D. Assume equal probabilities of f_e for each cell and make sure to report all relevant statistics, including the value of χ² obtained, the critical value and your decision as to whether to reject the null hypothesis

• Data Set D

  12

  20

  16

  18

  30

Answer 1

Ans:

Total number of observations=12+20+16+18+30=96

Expected frequency for each cell=96/5=19.2

	Observed(fo)	Expected(fe)	(fo-fe)^2/fe
1	12	19.2	2.700
2	20	19.2	0.033
3	16	19.2	0.533
4	18	19.2	0.075
5	30	19.2	6.075
Total	96	96	9.417

Test statistic:

Chi square=9.417

df=5-1=4

p-value=CHIDIST(9.417,4)=0.0515

Critical chi square=CHIINV(0.05,4)=9.488

As,test statistic is less than critical chi square,so we fail to reject H₀.