The average driving distance (yards) and driving accuracy(percent of drives that land in the fairway) for 8 golfers are recorded in the table to the right. Complete parts a through e below. |
Player |
Distance (yards) |
Accuracy (%) |
||
---|---|---|---|---|---|
1 |
316.1 |
44.6 |
|||
2 |
303.3 |
51.7 |
|||
3 |
309.4 |
47.5 |
|||
4 |
311.6 |
40.6 |
|||
5 |
295.3 |
55.4 |
|||
6 |
290.4 |
58.9 |
|||
7 |
295.8 |
56.2 |
|||
8 |
304.3 |
49.5 |
a. Write the equation of a straight-line model relating driving accuracy (y) to driving distance (x). Choose the correct answer below.
A. y=β1x
B.y equals beta 1 x squared plus beta 0y=β1x2+β0
C.y equals beta 1 x plus epsilony=β1x+ε
D.y equals beta 0 plus beta 1 x plus epsilony=β0+β1x+ε
Your answer is correct
.b. Fit the model, part a, to the data using simple linear regression. Give the least squares prediction equation.Modifying
Above y with carety=(250.3) plus+ left parenthesis negative 0.6587 right parenthesis(−0.6587) xc.
Interpret the estimated y-intercept of the line. Choose the correct answer below.
A.Since a drive with 0% accuracy is outside the range of the sample data, the y-intercept has no practical interpretation.
B.For each additional yard in distance, the accuracy is estimated to change by the value of the y-intercept.
C.For each additional percentage in accuracy, the distance is estimated to change by the value of they-intercept.
D.Since a drive with distance 0 yards is outside the range of the sample data, the y-intercept has no practical interpretation.
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