Conduct a test at the alphaequals0.05 level of significance by determining (a) the null and alternative hypotheses, (b) the test statistic, and (c) the P-value. Assume the samples were obtained independently from a large population using simple random sampling. Test whether p 1 greater than p 2. The sample data are x 1 equals 126, n 1 equals 251, x 2 equals 137, and n 2 equals 304.
(b) Determine the test statistic. z0 equals ? (Round to two decimal places as needed.)
For sample 1: n1=251, x1=126
Sample proportion, = 126/251 = 0.502
For sample 2: n2=304, x2=137
Sample proportion, = 137/304 = 0.4507
The value of the pooled proportion is computed =
a) Null and Alternative Hypotheses
b) Test Statistics:
c) P-value for right tailed test using excel
=1- NORM.S.DIST(1.205,1) = 0.1141
P-value = 0.1141
As p = 0.114 >0.05, it is concluded that the null hypothesis is not rejected.
Therefore, there is not enough evidence to claim that the population proportion p1 is greater than p2, at the 0.05 significance level.
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