Claim: The mean pulse rate (in beats per minute) of adult males is equal to 69bpm. For a random sample of 156 adult males, the mean pulse rate is 68.4 bpm and the standard deviation is 10.8 bpm. Find the value of the test statistic.
The value of the test statistic is = ??
(Round to two decimal places as needed.)
this is the two tailed test .
The null and alternative hypothesis is ,
H0 : = 69
Ha : 69
Test statistic = z
= ( - ) / / n
= (68.4-69) / 10.8/ 1156
= -0.69
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