Question

Minimally invasive procedures (requiring only small incisions) attempt to reduce the damage to human tissue that...

Minimally invasive procedures (requiring only small incisions) attempt to reduce the damage to human tissue that results from performing surgery. These procedures typically require small “ports” from which the surgeon inserts thin tubes called trocars. Specialized surgical equipment and miniature camera(s) are then placed through the trocars to conduct the surgery, resulting in less tissue damage than traditional “open” surgeries (which may require a large incision). There are even minimally invasive surgical procedures that can be performed almost exclusively through a single point of entry (i.e., requiring only one small incision).

Minimally invasive procedures have been shown to have equivalent outcomes to traditional surgeries while also reducing human tissue damage. It has also been hypothesized that such minimally invasive procedures reduce the length of hospitalization, with corresponding reductions in postoperative bleeding, scarring, and patient-reported pain.

For a particular type of traditional “open” surgery, the average length of hospitalization following the procedure is 5.8 days.

A random sample of 36 patients needing this particular type of surgery agreed to minimally invasive techniques for the surgical procedure. Using a 1% significance level, test the claim that the mean length of hospitalization (days) is less than that of the traditional “open” surgery (i.e., less than 5.8 days).

a. Using proper notation, write out the null and alternative hypotheses for this test:

Ho:

H1:

b. Specify what type of statistical procedure would have been utilized for this particular analysis (e.g., two tailed, one sample z-test).

c. If appropriate for the statistical procedure, what would the degrees of freedom (df) be?

d. Assume that the reported test statistic for the analysis was t = - 6.215 with a corresponding p-value less than .0001. In one to two complete sentences, what can you conclude from the test results provided?

Homework Answers

Answer #1

a. We are testing,

H0: u= 5.8 vs H1: u<5.8

b. Since the population s.d of the time of hospitalization following the surgery is not given, we we will be using a one sample t test. (AsuumiAs the sample mean and s.d is normally distributed)

c. The appropriate degrees of freedom= n-1 ie 35 here.

d. Since the p-value of our test statistic is significantly less than 1%, we have sufficient evidence to reject H0 at the 1% level and conclude that the mean length of hospitalization is less than 5.8 days.

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
I only need/want question #4 answered. Only Question 4! Thanks! Twin Falls Community Hospital is a...
I only need/want question #4 answered. Only Question 4! Thanks! Twin Falls Community Hospital is a 250-bed, not-for-profit hospital located in the city of Twin Falls, the largest city in Idaho’s Magic Valley region and the seventh largest in the state. The hospital was founded in 1972 and today is acknowledged to be one of the leading healthcare providers in the area. Twin Falls’ management is currently evaluating a proposed ambulatory (outpatient) surgery center. Over 80 percent of all outpatient...
n what follows use any of the following tests/procedures: Regression, multiple regression, confidence intervals, one sided...
n what follows use any of the following tests/procedures: Regression, multiple regression, confidence intervals, one sided T-test or two sided T-test. All the procedures should be done with 5% P-value or 95% confidence interval.Some answers are approximated, choose the most appropriate answer. Open Pollution data. SETUP: Is it reasonable to claim that cities with precipitation of less than 100 days have average temperature of less than 65 degrees F? Given the data your job is to confirm or disprove this...
HELMINTH GENUS NAMES TO MATCH TO THE CASE STUDY:       Taenia Ascaris Enterobius Schistosoma Trichinella Case 1:...
HELMINTH GENUS NAMES TO MATCH TO THE CASE STUDY:       Taenia Ascaris Enterobius Schistosoma Trichinella Case 1: A 4-year-old female arrived at the emergency department with abdominal pain, vomiting and a 3-day history of diarrhea. She also exhibited tachycardia, bloating with no bowel sounds, and a palpable mass in the area of the right ileum. An X-ray of the area revealed air fluid levels and the shadow of roundworms in a “whirlpool” image. The ileum was nearly obstructed, and the patient...
READ THE CASE STUDY AND ANSWER THE FOLLOWING QUESTIONS 2nd CASE: An Unexplained Death A 65-year-old...
READ THE CASE STUDY AND ANSWER THE FOLLOWING QUESTIONS 2nd CASE: An Unexplained Death A 65-year-old man of Scandinavian descent was rushed to the Emergency Room of your local hospital after a family member discovered him unconscious in his home. The woman who dialed “911” told the dispatcher that the man, her brother, was the local librarian of the past 10 years and had no spouse or children. She reported that they had spoken the day before, and he had...
Sign In INNOVATION Deep Change: How Operational Innovation Can Transform Your Company by Michael Hammer From...
Sign In INNOVATION Deep Change: How Operational Innovation Can Transform Your Company by Michael Hammer From the April 2004 Issue Save Share 8.95 In 1991, Progressive Insurance, an automobile insurer based in Mayfield Village, Ohio, had approximately $1.3 billion in sales. By 2002, that figure had grown to $9.5 billion. What fashionable strategies did Progressive employ to achieve sevenfold growth in just over a decade? Was it positioned in a high-growth industry? Hardly. Auto insurance is a mature, 100-year-old industry...