Recall that there are 52 cards in a deck, with four suits of 13 cards each. Determine the weight associated with the following card hand: having 7 cards of the same suit.
I worked this same problem with a friend who had a different number of cards: 9 cards of the same suit. I used the formula W=(N!)/(a0!)(a1!); substituting the variables, I concluded that W=4*(13!/((7!)(6!)). This method worked for my friend and he got the correct answer, but I did not. What am I doing wrong if anything?
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