A university financial aid office polled a random sample of 837 male undergraduate students and 732 female undergraduate students. Each of the students was asked whether or not they were employed during the previous summer. 566 of the male students and 446 of the female students said that they had worked during the previous summer. Give a 98% confidence interval for the difference between the proportions of male and female students who were employed during the summer.
Step 1 of 3: Find the point of estimate that should be used in constructing the confidence interval. Round your answers to three decimal places.
Step 2 of 3: Find the margin of error. Round your answer to six decimal places.
Step 3 of 3: Construct the 98% confidence interval. Round your answers to three decimal places.
The statistical software output for this problem is:
Hence,
Step - 1: Point estimate = 0.067
Step - 2: Margin of error = (0.123288 - 0.010582)/2 = 0.056353
Step - 3: 98% confidence interval:
(0.011, 0.123)
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