For the data set:
x | y |
-3 | -3 |
3 | 3 |
6 | 6 |
8 | 7 |
12 | 11 |
carry out the hypothesis test
H0:β1=0
H1:β1≠0
Determine the value of the test statistic and the associated p-value.
Test Stat =
p-Val =
H0:β1=0
H1:β1≠0
From above table we have
t= coefficient of β1/SE
t= 0.924/0.035
t= 26.21
P value= 0.000122
Since P value SMALLER than 0.05 level of significance therefore SIGNIFICANT.
Decision: REJECT NULL HYPOTHESIS H0.
Conclusion: We have sufficient evidence to show that β1 is different from ZERO.
NOTE: I used MS EXCEL data analysis tool pack.
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