Question

Let X~GEOM(0.7). Let Y=e^2x. Find E[Y].

Let X~GEOM(0.7). Let Y=e^2x. Find E[Y].

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Answer #1

here E(Y)=e2xf(x) =e2x*(1-0.7)x-10.7 =(1/0.3)*e2x*0.3x*0.7 =(0.7/0.3)*(0.3e2)x

here as (0.3e2)x is geometric series with common ratio of 0.3e2 which is greater then 1 ; therefore sum of the series is infinite,

E(Y)=(7/3)* =

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