Question

Assume a normal distribution. (Give your answer correct to two decimal places.)

(a) Find the z-score associated with the 59th percentile.

(b) Find the z-score associated with the 82nd percentile.

(c) Find the z-score associated with the 92nd percentile.

Answer #1

**Answer:**

Given that,

Assume a normal distribution.

**(a).**

**Find the
z-score associated with the 59th percentile:**

P(Z < z)=59%

P(Z < z)=0.59

[Since from normal distribution table]

P(Z < 0.23)=0.59

**z=0.23**

**(b).**

**Find the
z-score associated with the 82nd percentile:**

P(Z < z)=82%

P(Z < z)=0.82

[Since from normal distribution table]

P(Z < 0.92)=0.82

**z=0.92**

**(c).**

**Find the
z-score associated with the 92nd percentile:**

P(Z < z)=92%

P(Z < z)=0.92

[Since from normal distribution table]

P(Z < 1.41)=0.92

**z=1.41**

Consider the following. (Give your answers correct to two
decimal places.)
(a) Find the standard score (z) such that the area
below the mean and above z under the normal curve is
0.3961.
(b) Find the standard score (z) such that the area below
the mean and above z under the normal curve is
0.4812.
(c) Find the standard score (z) such that the area below
the mean and above z under the normal curve is 0.3733.

Consider the following. (Give your answers correct to two
decimal places.) (a) Find z(0.1). (b) Find z(0.26). (c) Find
z(0.7). (d) Find z(0.92).
You may need to use the appropriate table in Appendix B to
answer this question.

1. For a standard normal distribution,
find:
P(z > 2.32)
Keep four decimal places.
2. For a standard normal distribution,
find:
P(-0.9 < z < 0.95)
3. For a standard normal distribution,
given:
P(z < c) = 0.7622
Find c.
4. For a standard normal distribution,
find:
P(z > c) = 0.1753
Find c
5. Assume
that the readings at freezing on a batch of thermometers
are normally distributed with a mean of 0°C and a standard
deviation of 1.00°C....

Assume that z is the test statistic. (Give your answers
correct to two decimal places.)
(a) Calculate the value of z for
Ho: μ = 10, σ = 2.5,
n = 39, x = 10.7.
(b) Calculate the value of z for Ho:
μ = 120, σ = 30, n = 21, x =
126.2.
(c) Calculate the value of z for Ho:
μ = 18.2, σ = 3.7, n = 145, x =
18.85.
(d) Calculate the value of...

Write only a number as your answer. Round to two decimal
places.
1.) Find the z-score for which the area to its right is
0.45.
2.) Find the z-score for which the area to its left is 0.58.
3.) Find the z-score for which the area to its right is
0.49.
4.) Find the z-score for which the area to its left is 0.40.

A normal distribution has μ = 32 and σ =
5.
(a) Find the z score corresponding to
x = 27.
(b) Find the z score corresponding to
x = 44.
(c) Find the raw score corresponding to
z = −3.
(d) Find the raw score corresponding to
z = 1.9.
(e)Sketch the area under the standard normal curve over the
indicated interval and find the specified area. (Round your answer
to four decimal places.)
The area between
z =...

Consider the following. (Give your answers correct to four
decimal places.)
(a) Find P(-2 < z < 0.00).
(b) Find P(-1.87 < z < 2.07).
(c) Find P(z < -1.44).
(d) Find P(z < -0.45).
(e) Find P(-3.1 < z < 0.00).
(f) Find P(-2.41 < z < 1.34).
(g) Find P(z < -2.23).
(h) Find P(z > 2.34).

Using a normal distribution and z score formula answer
the following questions
a. Find the score that cuts off the bottom 35% of the
normal curve
b. Find the data value to the nearest whole number that
cuts off the op 10% of the curve given
that the mean is 75 and sample standard deviation is
5
C Find the z scores that cut off the middle 60% of the
normal curve.

1)A normal distribution has μ = 24 and σ =
5.
(a) Find the z score corresponding to
x = 19.
(b) Find the z score corresponding to
x = 35.
(c) Find the raw score corresponding to
z = −2.
(d) Find the raw score corresponding to
z = 1.7.
2)Sketch the area under the standard normal curve over the
indicated interval and find the specified area. (Round your answer
to four decimal places.)
The area to the left...

For the standard normal distribution, find the values (to 2
decimal places) of z such that
22% of values are below z:
54% of values are below z:

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