Question

1. Below is an ANOVA table that is incomplete but has enough information provided to be completed.

Source SS df MS F

Between 910 2

Within 70

Total 59

a. (4 points) Complete the One-Way ANOVA table.

b. (2 points) Determine the critical F at =.05. Should we reject the null?

c. (2 points) How many different groups were in this study? Assuming equal numbers in each group, how many participants were in each group?

d. (4 points) Calculate eta-squared and omega-squared for this ANOVA.

Answer #1

a.

Source SS df MS F

Between (effect) 910 2 455 358.26

Within (error) 70 57 1.27

Total 980 59

df for within = df Total - df Between = 59 - 2 = 57

SS Total = SS Between + SS Error = 910 + 70 =980

MS = SS / df

b.

Critical values of F at = 0.05 and df = 2, 57 is 3.16

Since observed F is greater than critical value, we reject the null.

c.

Number of groups = df between + 1 = 2 + 1 = 3

Total participants = df Total + 1 = 59 + 1 = 60

Number of participants in each group = 60 / 3 = 20

d.

eta-squared = SS between / SS total = 910 / 980 = 0.9286

omega-squared =
SS_{effect}-(df_{effect})(MS_{error}) /
(MS_{error} + SS_{total)}

= (910 - 2 * 1.27) / (1.27 + 980)

= 0.9248

3. Refer to the following ANOVA Summary Table
to answer the questions listed below it.
SOURCE
SS
df
MS
F
Between
23.57
3
.
Within
24
.95
Total
46.43
Answer each of these questions concerning this ANOVA
Summary Table:
What is SS within?
Your Answer:
.
What is MS between?
Your Answer:
.
What is df total?
Your Answer:
.
What is the observed...

The following is an incomplete F-table summarizing the
results of a study of the variance of life satisfaction scores
among unemployed, retired, part-time, and full-time employees.
Source of Variation
SS
df
MS
F
Between
groups
21
Within
groups (error)
36
Total
139
(a) Complete the F-table. (Round your values for mean
squares and F to two decimal places.)
Source of Variation
SS
df
MS
F
Between
groups
3
21
Within
groups (error)...

10a
The following is an incomplete ANOVA table.
Source of Variation
SS
df
MS
F
Between groups
2
11.7
Within groups
Total
90
10
The value of the test statistic is
Multiple Choice
11.7
90
8.325
1.405

The following is an incomplete ANOVA table.
Source of Variation
SS
df
MS
F
Between groups
2
11.8
Within groups
Total
100
10
The p-value of the test is
a) less than 0.14
b) between 0.01 and 0.038
c) between 0.025 and 0.18
d) greater tha

6. (36 pts) The following is an incomplete
ANOVA summary table:
Source
df
SS
MS
F
Among Groups
3
63
Within Groups
16
97
Total
(a) Complete the ANOVA summary table.
(b) Determine the number of groups.
(b) At the α = 0.05 level of significance, determine whether
there is evidence of difference in the population means.

The following is an incomplete F-table summarizing the
results of a study of the variance of life satisfaction scores
among unemployed, retired, part-time, and full-time employees.
Source of Variation
SS
df
MS
F
Between
groups
17
Within
groups (error)
36
Total
131
(a) Complete the F-table. (Round your values for mean
squares and F to two decimal places.)
Source of Variation
SS
df
MS
F
Between
groups
17
Within
groups (error)
36
Total
131
(b) Compute omega-squared
(ω2).
(Round your...

The following is an incomplete F-table summarizing the
results of a study of the variance of life satisfaction scores
among unemployed, retired, part-time, and full-time employees.
Source of Variation
SS
df
MS
F
Between
groups
20
Within
groups (error)
36
Total
148
(a) Complete the F-table. (Round your values for mean
squares and F to two decimal places.)
Source of Variation
SS
df
MS
F
Between
groups
20
Within
groups (error)
36
Total
148
(b) Compute omega-squared
(ω2).
(Round your...

In computing an ANOVA involving four groups of 12 each, the
following partially completed ANOVA table was given. Complete this
table.
Source
SS
df
MS
F
Between
9
Within
Total
20

Complete the following ANOVA table to answer the
question
Source
df
MS
f
F CRIT
City_Size (A)
2
380
Gender (B)
1
20
AxB
70
Error
100
Total
59
The partial eta-squared due to interaction
is
A..583
B. Insufficient data. It cannot be estimated from the
data
C. .206
D. .185

Consider the partial ANOVA table shown below. Let a = .01
Source of Variation
DF
SS
MS
F
Between Treatments
3
180
Within Treatments (Error)
Total
19
380
If all the samples have five observations each:
there are 10 possible pairs of sample means.
the only appropriate comparison test is the Tukey-Kramer.
all of the absolute differences will likely exceed their
corresponding critical values.
there is no need for a comparison test – the null hypothesis is
not rejected.
2...

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