M/D/1.
Arrivals: Average time between customer arrivals, IAT=7 minutes.
Service:The service station is now automated, no variability in service time exists. The time required to complete a job is exactly 6 minutes.
Wq=
18min |
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10min |
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20min |
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need more information |
Here arrival time = 7 mins
arrival rate = = (1/7) min-1
Service time = 6 mins
service rate = = (1/6) min-1
Utilization rate = = / = 6/7
The average waiting time in the queue (line), ω Q is given by = /[2(1 - )] = (6/7) / [2 * 1/6 * (1 - 6/7)]
= (6/7)/(2 * 1/6 * 1/7)
= 18 min
Option A is correct.
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