Question

When people smoke, the nicotine they absorb is converted to cotinine, which can be measured. A...

When people smoke, the nicotine they absorb is converted to cotinine, which can be measured. A sample of 40 smokers has a mean cotinine level of 172.5 ng/ml. Assuming the σ is known to be 119.5 ng/ml, find the following: (6 pts)

a) A 90% confidence interval estimate of the mean cotinine level of all smokers.

b) A 98% confidence interval estimate of the mean cotinine level of all smokers.

c) A 92% confidence interval estimate of the mean cotinine level of all smokers.

Math   Statistics-And-Probability   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

Given that, sample size (n) = 40

sample mean =172.5 ng/ml

Population standard deviation = 119.5 ng/ml

Using TI-84 calculator we get the following confidence interval estimates.

a) A 90% confidence interval estimate of the mean cotinine level of all smokers is , (141.42, 203.58)

b) A 98% confidence interval estimate of the mean cotinine level of all smokers is, (128.54, 216.46)

c) A 92% confidence interval estimate of the mean cotinine level of all smokers is, (139.42, 205.58)

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
When people smoke, the nicotine they absorb is converted to cotinine, which can be measured. A...
When people smoke, the nicotine they absorb is converted to cotinine, which can be measured. A sample of 70 smokers has a mean cotinine level of 172.3 ng/ml and a stadard deviation of 118.2 ng/ml. What is the value of the test statistic when testing the claim that the mean cotinine level of all smokers is less than 200.0 ng/ml at the significance level 5%? Select one: a. -1.64 b. 1.64 c. None of the other answers is neccessary true....
1) A sample of cereal boxes is randomly selected and the sugar contents (grams of sugar...
1) A sample of cereal boxes is randomly selected and the sugar contents (grams of sugar per gram of cereal) are recorded. Those amounts are summarized with these statistics: n = 16, ?̅ = 0.295g, s = 0.168g. Use a 0.05 significance level to test the claim that the mean of all cereals is less than 0.3g. Section 7-6 Problem Testing a Claim about a Standard Deviation a ) Use a 0.05 significance level to test the claim that heights...
CH 8.1) Health insurers are beginning to offer telemedicine services online that replace the common office...
CH 8.1) Health insurers are beginning to offer telemedicine services online that replace the common office visit. Wellpoint provides a video service that allows subscribers to connect with a physician online and receive prescribed treatments. Wellpoint claims that users of its LiveHealth Online service saved a significant amount of money on a typical visit. The data shown below ($), for a sample of 20 online doctor visits, are consistent with the savings per visit reported by Wellpoint. 92 35 40...
Biologists studying the healing of skin wounds measured the rate at which new cells closed a...
Biologists studying the healing of skin wounds measured the rate at which new cells closed a cut made in the skin of an anesthetized newt. Here are data from a random sample of 18 newts, measured in micrometers (millionths of a meter) per hour: 29, 27, 34, 40, 22, 28, 14, 35, 26, 35, 12, 30, 23, 18, 11, 22, 23, 33. 90% confidence level (22.254,29.080) (A) Consider a test of H0 : μ = 25 vs. HA : μ...
From generation to generation, the mean age when smokers first start to smoke varies. However, the...
From generation to generation, the mean age when smokers first start to smoke varies. However, the standard deviation of that age remains constant at around 2.1 years. A survey of 39 smokers of this generation was done to see if the mean starting age is at least 19. The sample mean was 18.1 with a sample standard deviation of 1.3. Do the data support the claim at the 5% level? 1. State the distribution to use for the test. (Round...
One of the most important factors in blood coagulation and clot formation in humans is a...
One of the most important factors in blood coagulation and clot formation in humans is a protein called prothrombin, which must be converted into the enzyme thrombin in order for coagulation to occur. A random sample was taken from a population with a vitamin K deficiency (typically a population that has a low prothrombin level) and the results are given below, measured in mgdL: S={18.70,19.45,23.40,21.8,19.54,22.19,20.14,20.37,23.02,19.46,18.98} It is known that the population standard deviation prothrombin levels of a population is about...
Biologists studying the healing of skin wounds measured the rate at which new cells closed a...
Biologists studying the healing of skin wounds measured the rate at which new cells closed a cut made in the skin of an anesthetized newt. Here are data from a random sample of 18 newts, measured in micrometers (millionths of a meter) per hour: 29, 27, 34, 40, 22, 28, 14, 35, 26, 35, 12, 30, 23, 18, 11, 22, 23, 33 (a) Create a QQ plot of the data. Do you think it is reasonable to assume that the...
a.In a survey, 21 people were asked how much they spent on their child's last birthday...
a.In a survey, 21 people were asked how much they spent on their child's last birthday gift. The results were roughly bell-shaped with a mean of $40 and standard deviation of $9. Construct a confidence interval at a 80% confidence level. Give your answers to one decimal place. b. If n=30, ¯x¯(x-bar)=48, and s=9, find the margin of error at a 80% confidence level Give your answer to two decimal places. c. In a survey, 22 people were asked how...
1. Costs are rising for all kinds of health care. The mean monthly rent at assisted-living...
1. Costs are rising for all kinds of health care. The mean monthly rent at assisted-living facilities was recently reported to have increased 18% over the last five years. A recent random sample of 121 observations reported a sample mean of $3486. Assume that past studies have informed us that the population standard deviation is $650. For this problem, round your answers to 2 digits after the decimal point. (a) What are the end points of a 90% confidence-interval estimate...
In a July 2001 research note, the U.S. Department of Transportation reported the results of the...
In a July 2001 research note, the U.S. Department of Transportation reported the results of the National Occupant Protection Use Survey. One focus of the survey was to determine the level of cell phone use by drivers while they are driving a motor passenger vehicle. Data collected by observers at randomly selected intersection across the country revealed that in a sample of 1165 drivers, 35 were using their cell phone. (a) Check and verify the two conditions for a 98%...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT