When people smoke, the nicotine they absorb is converted to cotinine, which can be measured. A sample of 40 smokers has a mean cotinine level of 172.5 ng/ml. Assuming the σ is known to be 119.5 ng/ml, find the following: (6 pts)
a) A 90% confidence interval estimate of the mean cotinine level of all smokers.
b) A 98% confidence interval estimate of the mean cotinine level of all smokers.
c) A 92% confidence interval estimate of the mean cotinine level of all smokers.
Given that, sample size (n) = 40
sample mean =172.5 ng/ml
Population standard deviation = 119.5 ng/ml
Using TI-84 calculator we get the following confidence interval estimates.
a) A 90% confidence interval estimate of the mean cotinine level of all smokers is , (141.42, 203.58)
b) A 98% confidence interval estimate of the mean cotinine level of all smokers is, (128.54, 216.46)
c) A 92% confidence interval estimate of the mean cotinine level of all smokers is, (139.42, 205.58)
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