Question

19.

A newspaper company classifies its customers by gender and location of residence. The research department has gathered data from a random sample of 1518 customers. The data is summarized in the table below.

Gender and Residence of Customers
Residence	Males	Females
Apartment	288	71
Dorm	223	296
With Parent(s)	77	134
Sorority/Fraternity House	71	58
Other	117	183

What is the probability that a customer is not male or does not live with their parents? Express your answer as a fraction or a decimal number rounded to four decimal places.

Answer 1

Solution:
We need to find
P(Customer is not male or does not live with thier parents) = P(Customer is not male) +P(Customer is not living with their parants) -P(Customer is not male and Customer not living with their parants)
P(Customer is not male) = (71+296+134+58+183)/1518 = 742/1518 = 0.4888
P(Customer is not living with their parants) = (288+71+223+296+71+58+117+183)/1518 = 1307/1518 = 0.86100
P(Customer is not male and not live with their parants) = (71+296+58+183)/1518 = 608/1518 = 0.4005
P(Customer is not male or not liing with their parents) = (742+1307-608)/1518 = 1441/1518 = 0.9492

So there is 94.92% probability that a customer is not male or does not live with their parents.
Or we can calculate as
P(Customer is not male or not liing with their parents) =1-P(Cutomer is male and living with their parents) = 1 - (77/1518) = 0.9492 or 94.92%