Question

1. Fifty-four percent of Americans have taken a sick day when they are really not sick. A survey of 400 people from Pennsylvania indicates that 204 of them have taken a sick day when they were not sick. Construct and interpret a 95% confidence interval for the true percentage of Pennsylvanians who have taken a sick day while not being sick.

Answer 1

for 95% CI z = 1.96

So, the 95% confidence interval is between 46.1% to 55.9%.

Interpretation: One is 95% confident that the true percentage of Pennsylvanians who have take a sick day while not being sick is between 46.1% to 55.9%.

Please comment if any doubt. Thank you.