A sample of 900 computer chips revealed that 59% of the chips fail in the first 1000 hours of their use. The company's promotional literature states that 62% of the chips fail in the first 1000 hours of their use. The quality control manager wants to test the claim that the actual percentage that fail is less than the stated percentage. Is there enough evidence at the 0.10 level to support the manager's claim?
Step 1 of 7:
State the null and alternative hypotheses.
P =Population Proportion = 0.62
Q = 1 - P = 0.38
n = Sample Size = 900
SE =
Test statistic is:
Z = (0.59 -0.62)/0.0162 = - 1.8542
= 0.10
From Table, critical value of Z = - 1.28
Since calculated value of Z is less than critical valueof Z, the difference is significant. Reject null hypothesis.
Conclusion:
There is enough evidence at the 0.10 level to support the manager's claim.
Answer to question asked:
State the null and alternative hypothesis.
H0:Null Hypothesis: P 0.62
HA: Alternative Hypothesis: P < 0.62
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