Question

A one-way analysis of variance experiment produced the following ANOVA table. (You may find it useful...

A one-way analysis of variance experiment produced the following ANOVA table. (You may find it useful to reference the q table).

SUMMARY
Groups Count Average
Column 1 6 0.72
Column 2 6 1.74
Column 3 6 2.51
  Source of Variation SS df MS F p-value
Between Groups 8.50 2 4.25 16.35 0.0002
Within Groups 3.93 15 0.26
Total 12.43 17

b. Calculate 99% confidence interval estimates of μ1μ2,μ1μ3, and μ2μ3 with Tukey’s HSD approach. (If the exact value for nTc is not found in the table, then round down. Negative values should be indicated by a minus sign. Round intermediate calculations to at least 4 decimal places. Round your answers to 2 decimal places.)

Population Mean Differences Confidence Interval
μ1 − μ2 [ , ]
μ1 − μ3 [ , ]
μ2 − μ3 [ , ]

Homework Answers

Answer #1

Critical value for , df=15 and k=3 is

And

The Tukey's HSD will be

Following table shows the confidence intervals

The required confidence intervals are:

groups (i-j) Lower limit Upper limit
mu1-mu2 -2.03 -0.01
mu1-mu3 -2.8 -0.78
mu2-mu3 -1.78 0.24
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