A one-way analysis of variance experiment produced the following ANOVA table. (You may find it useful to reference the q table).
SUMMARY | ||||||
Groups | Count | Average | ||||
Column 1 | 6 | 0.72 | ||||
Column 2 | 6 | 1.74 | ||||
Column 3 | 6 | 2.51 | ||||
Source of Variation | SS | df | MS | F | p-value | |
Between Groups | 8.50 | 2 | 4.25 | 16.35 | 0.0002 | |
Within Groups | 3.93 | 15 | 0.26 | |||
Total | 12.43 | 17 | ||||
b. Calculate 99% confidence interval estimates of μ1 − μ2,μ1 − μ3, and μ2 − μ3 with Tukey’s HSD approach. (If the exact value for nT – c is not found in the table, then round down. Negative values should be indicated by a minus sign. Round intermediate calculations to at least 4 decimal places. Round your answers to 2 decimal places.)
|
Critical value for , df=15 and k=3 is
And
The Tukey's HSD will be
Following table shows the confidence intervals
The required confidence intervals are:
groups (i-j) | Lower limit | Upper limit |
mu1-mu2 | -2.03 | -0.01 |
mu1-mu3 | -2.8 | -0.78 |
mu2-mu3 | -1.78 | 0.24 |
Get Answers For Free
Most questions answered within 1 hours.