2.3 Consider the data in the following two sequences
AB Sequence
Patient | Period 1 | Period 2 |
1 | 310 | 270 |
2 | 310 | 260 |
3 | 370 | 300 |
4 | 410 | 390 |
5 | 250 | 210 |
6 | 380 | 350 |
7 | 330 | 365 |
8 | 310 | 320 |
9 | 340 | 275 |
10 | 365 | 285 |
11 | 280 | 330 |
12 | 345 | 240 |
13 | 320 | 310 |
14 | 330 | 300 |
BA Sequence
Patient | Period 1 | Period 2 |
1 | 370 | 385 |
2 | 310 | 400 |
3 | 380 | 410 |
4 | 290 | 320 |
5 | 260 | 340 |
6 | 90 | 220 |
7 | 340 | 390 |
8 | 375 | 395 |
9 | 330 | 350 |
10 | 315 | 365 |
11 | 330 | 300 |
12 | 175 | 280 |
1.Carry out all the necessary tests and make any relevant comments against each.
2. Plot all the necessary graphs and make necessary conclusions
3. ANOVA
AB Sequence:
Bring data in to excel sheet.
select data --> go to data analysis --> choose Anova single factor
P value = 0.8
You will fail to reject the null hypothesis if the p-value is greater than or equal to the level of significance.
Create line graph to find which period is higher
Period 1 is higher than the period 2
BA Sequence:
P-value = 0.11
You will fail to reject the null hypothesis if the p-value is greater than or equal to the level of significance.
conclusion:
Period 2 is higher than the period 1
Get Answers For Free
Most questions answered within 1 hours.