Question

If the confidence level is 99% and sample size is 36, how much is t(1-α/2, n-1)? A. 2.0639 B. 2.0595 C. 2.7238 D. 2.7195

Answer 1

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The confidence level is 99%

The sample size is 36, therefore the degree of freedom is n-1 = 36-1 = 35

Hence, from the t-tables or through the excel formula we find the t value in the following way:

= T.INV(0.005, 35) , you can see that 1-a/2 = 1-.99/2 = .01/2 = .005, and n-1 = 36-1 =35

The above formula gives : t = -2.7238, C is correct ( we ignore the -ive sign as it is a confidence interval and therefore t value is used both sides for confidence interval)

C is correct