You want to obtain a sample to estimate a population proportion.
Based on previous evidence, you believe the population proportion
is approximately p∗=19%p∗=19%. You would like to be 99.5% confident
that your estimate is within 0.5% of the true population
proportion. How large of a sample size is required?
n =
Do not round mid-calculation. However, use a critical value accurate to three decimal places.
Solution :
Given that,
= 19%=0.19
1 - = 1 - 0.19 = 0.81
margin of error = E = 0.5% = 0.005
At 99.5% confidence level the z is ,
Z/2 = 2.807( Using z table )
Sample size = n = (Z/2 / E)2 * * (1 - )
= (2.807/ 0.005)2 * 0.19 * 0.81
= 48504.65
Sample size =48505
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