If your population standard deviation is 66.04, then how many people do you need to sample at a minimum to ensure with 95% confidence that you have a maximal margin of error of 1.32?
Round your answer to the nearest whole number
Solution:
Given ,
= 66.04 ..Population SD
E = 1.32 Margin of error
c = 95% =0.95 ...confidence level
= 1- c = 1- 0.95 = 0.05
/2 = 0.05 2 = 0.025 and 1- /2 = 0.975
Search the probability 0.975 in the Z table and see corresponding z value
= 1.96
Now, sample size (n) is given by,
= {(1.96* 66.04)/ 1.32 }2
= 9615.64473976
= 9616 ..(round to the next whole number)
Answer : 9616
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