In order to find a 90% confidence interval we need to find values aa and bb such that for Z∼N(μ=0,σ=1),Z∼N(μ=0,σ=1),
P(a<Z<b)=0.9.
(a) Suppose a=−2.5562.a=−2.5562. Then b=
(b) Suppose b=2.9501.b=2.9501. Then a=
By using online calculator, trying different values of b to get 0.9 area [for (a) by fixing a =−2.5562] and trying different values of a to get 0.9 area [for (b) by fixing b =2.9501].
(a)
P(−2.5562 < Z < 1.3125) =0.9
Therefore, b =1.3125
(b)
P(-1.2905 < Z < 2.9501) =0.9
Therefore, a = -1.2905
By using the table of "Area under Standard Normal Curve", it is solved as follows:
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