Black hair in rabbits is determined by a dominant allele, B, and white hair by homozygosity for a recessive allele, b. Two heterozygous rabbits mate and produce a little of five offspring. With what frequency would we expect to find: a) two whites and three black offspring? b) four white and one black offspring?
Here as we know from mendel experiment that when two heterozygous mates then the dominant allele will be shown 3 out of4 times and reccessive allele 1 out of 4 times.
Now here they produces 5 offspring.
and Pr(Black hair) = 3/4 and Pr(White hair) = 1/4
the distribution can be termed as binomial where x is the number of black hair offspring out of 5
f(x black hair offspring) = 5Cx (3/4)x(1/4)5-x = 0.2637
(a) Now we have to find the probability of
Pr(Two whites and three black offspring) = 5C3 (3/4)3(1/4)2 = 0.2637
(b Pr(Four white and one black offspring) = 5C4 (3/4)4(1/4)1 = 0.3955
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