Warranty: You buy a cell phone for $90 and there is a 6% chance that it will fail. You can pay an additional $9 for the hassle-free replacement warranty. This means if it fails you will get a free replacement.
(a) Suppose you do not buy the warranty but will buy a second one if the first one fails (we will assume this second one does not fail) and you will pay the full $90 for the second one. Complete the following table to assist in calculating the expected cost for this phone. Enter the probabilities to 2 decimal places.
Outcomes | cost = x | Probability = P(x) |
It fails | ||
It doesn't fail | ||
(b) Use the table to calculate the expected value for the cost of
this phone. Round your answer to the nearest
penny.
$
(c) Considering the expected cost above and the price of the
warranty ($9), did you make the right decision to not buy the
warranty and why? There is only one correct answer and
explanation.
Yes, because the expected cost is less than the cost of the phone plus the warranty.
No, because the expected cost is greater than the cost of the phone plus the warranty.
Yes, because the expected cost is greater than the cost of the phone plus the warranty.
No, because the expected cost is less than the cost of the phone plus the warranty.
P[ phone will fail ] = 6% = 0.06
P[ phone will not fail ] = 1 - 0.06 = 0.94
Cost of phone if it fails and one buys a new one = the actual cost of phone + cost of new phone*P[ 1st phone will fail ] = $90 + $90*0.06 = $90 + $5.4 = $95.4
Cost of phone if it does not fail = the actual cost of phone = $90
Outcomes | cost = x | Probability = P(x) |
It fails | 95.4 | 0.06 |
It doesn't fail | 90 | 0.94 |
b) Expected value for the cost of phone = sum( cost*P(x)) = 0.06*$95.4 + 0.94*$90 = $5.724 + $84.6 = $90.324
c) 1st option is correct
Yes, because the expected cost is less than the cost of the phone plus the warranty.
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