Question

A golf instructor is interested in determining if her new technique for improving players’ golf scores is effective.

She takes four new students and records their 18-hole scores before learning the new technique and then after
having taken her class. She then conducts a hypothesis test at a significance level of 5%.

The data are as follows.

	Player 1	Player 2	Player 3	Player 4
Mean score before class	83	78	93	87
Mean score after class	80	80	86	86

What is the Null Hypotheses?

What is the Alternate Hypothesis?

What is the significance level of the test?

What is the appropriate distribution for performing this test?

What is the critical value?

What is the numerical value of the test statistic?

What is the Pvalue for this hypothesis test.

Answer 1

P-Value:

We can find p- value using R:-

>pt(t-value,n-1,lower.tail=F)

>pt(3.998,3,lower.tail=F)

[1]0.0140257

P-Value=0.0140

Hence, we reject H₀