Question

A discrete RV Y can take one of 5 values -2, -1, 0, 1 and 2...

A discrete RV Y can take one of 5 values -2, -1, 0, 1 and 2 with equal probabilities. What is the CDF of the RV Y at y=1.5?

Homework Answers

Answer #1
x P(X = x) P(X < = x)
-2
-1
0
1
2

The cdf of Y can be written as


So, The CDF of the RV Y at y=1.5 = FY(1.5) = ​​​​​​​

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
91. Let X be a RV with support set {0, 1, 2}, p(1) = 0.3, and...
91. Let X be a RV with support set {0, 1, 2}, p(1) = 0.3, and p(2) = 0.5. Calculate E[X]. Let X be a discrete RV. Define the expected value E[X] of X. Is E[X] constant or random? Why? 92. Suppose X is a RV with support {−1,0,1} where p(−1) = q and p(1) = p. What relationship must hold between p and q to ensure that E[X] = 0? 93. Let X be a discrete RV and a,...
Consider a discrete random variable, q, that can take on the following values 1, 10, 100,...
Consider a discrete random variable, q, that can take on the following values 1, 10, 100, or 1000 with following probabilities.   q 1 10 100 1000 P(q) 0.15 0.23 0.45 0.18 Calculate the expected value of q Calculate the standard deviation of q
Consider two random variables X and Y . X can take the values 0, 1 and...
Consider two random variables X and Y . X can take the values 0, 1 and 2 andY cantakethevalues0and1. Youaretoldthat: P(X=0)=0.4,P(X=1)=0.2, P(Y =0|X=0)=0.4,P(Y =0|X=1)=0.2,P(Y =0|X=2)=0.3. Calculate P(Y =1),E(Y),Cov(X,Y),P(X=0|Y =0),P(Y =1|X+Y ≤2)
The values that a discrete random variable, X, can take are 1,2,3,4 with the probabilities 0.19,...
The values that a discrete random variable, X, can take are 1,2,3,4 with the probabilities 0.19, 0.22, 0.21, 0.38 respectively. Find the mean and variance of the probability distribution. Group of answer choices 2.58, 1.10 2.78, 1.34 2.61, 1.04 2.61, 1.10
Determine whether or not the distribution is a discrete probability distribution and select the reason why...
Determine whether or not the distribution is a discrete probability distribution and select the reason why or why not. x −2 6 7 P(X=x) −1/4 1/2 3/4 First, decide whether the distribution is a discrete probability distribution, then select the reason for making this decision. Yes     No               Reason Since the probabilities lie inclusively between 0 and 1 and the sum of the probabilities is equal to 1 . Since at least one of the probability values is greater than 1...
Let x and Y be two discrete random variables, where x Takes values 3 and 4...
Let x and Y be two discrete random variables, where x Takes values 3 and 4 and Y takes the values 2 and 5. Let furthermore the following probabilities be given: P(X=3 ∩ Y=2)= P(3,2)=0.3, P(X=3 ∩ Y=5)= P(3,5)=0.1, P(X=4 ∩ Y=2)= P(4,2)=0.4 and P(X=4∩ Y=5)= P(4,5)=0.2. Compute the correlation between X and Y.
Let x and Y be two discrete random variables, where x Takes values 3 and 4...
Let x and Y be two discrete random variables, where x Takes values 3 and 4 and Y takes the values 2 and 5. Let furthermore the following probabilities be given: P(X=3 ∩ Y=2)= P(3,2)=0.3, P(X=3 ∩ Y=5)= P(3,5)=0.1, P(X=4 ∩ Y=2)= P(4,2)=0.4 and P(X=4∩ Y=5)= P(4,5)=0.2. Compute the correlation between X and Y.
a) Let Z be a standart normal RV(random variable) and If Y = Z^2 for all...
a) Let Z be a standart normal RV(random variable) and If Y = Z^2 for all Z, what is the PDF and mean of Y ? b) If Y = Z^2 for Z>0 and Y=0 for other regitions, Calculate PDF of Y and P(Y=0). c) Calculate P(Y<1) by using table for both a and b options above.
Let X be a discrete random variable that takes on the values −1, 0, and 1....
Let X be a discrete random variable that takes on the values −1, 0, and 1. If E (X) = 1/2 and Var(X) = 7/16, what is the probability mass function of X?
The random variable X can take on the values 1, 2 and 3 and the random...
The random variable X can take on the values 1, 2 and 3 and the random variable Y can take on the values 1, 3, and 4. The joint probability distribution of X and Y is given in the following table: Y 1 3 4 X 1 0.1 0.15 0.1 2 0.1 0.1 0.1 3 0.1 0.2                         a. What value should go in the blank cell? b. Describe in words and notation the event that has probability 0.2 in...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT