A discrete RV Y can take one of 5 values -2, -1, 0, 1 and 2 with equal probabilities. What is the CDF of the RV Y at y=1.5?
x | P(X = x) | P(X < = x) |
-2 | ||
-1 | ||
0 | ||
1 | ||
2 |
The cdf of Y can be written as
So, The CDF of the RV Y at y=1.5 = FY(1.5) =
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