The cost of ink cartridges for inkjet printers can be substantial over the life of a printer. Printer manufacturers publish the number of pages that can be printed from an ink cartridge in an effort to attract customers. A company claims that its black ink cartridge will yield 495 pages. To test this claim, an independent lab measured the page count of 55 cartridges and found the average page count to be 486.6. Assume the standard deviation for this population is 45. Using a 95% confidenceinterval, does this sample support the company's claim? Select the correct choice below, and fill in the answer boxes to complete your choice. (Round to two decimal places asneeded.)
A. No, because the company's claim is not between the lower limit of ____ pages and the upper limit of ____ pages for the average number of pages yielded by a single black cartridge. B. Yes, because the company's claim is between the lower limit of ____ pages and the upper limit of ____ pages for the average number of pages yielded by a single black cartridge.
Answer:
Given,
xbar = 486.6
s = 45
n = 55
Here for the 95% confidence interval , z value is 1.96
Now consider,
Interval = (xbar +/- z*s/sqrt(n))
substitute values
= (486.6 +/- 1.96*45/sqrt(55))
= (486.6 +/- 11.8929)
= (486.6 - 11.8929 , 486.6 + 11.8929)
= (474.71 , 498.49)
Here we can say , Yes,the sample support the company's claim
i.e.,
495 is included in the CI limits.
So Option B is right answer.
Yes, because the company's claim is between the lower limit of 474.71 pages and the upper limit of 498.49 pages for the average number of pages yielded by a single black cartridge.
Get Answers For Free
Most questions answered within 1 hours.