Question

- It is known that the average American orders food from a
restaurant in person or as take out 4.2 times a week on average.
Suppose we take a sample of 30 Americans and find that the average
amount of meals ordered out is 3.2 per week with a sample standard
deviation of 2.82 meals. We are interested in testing if the
average amount of meals ordered out is actually lower than 4.2 now.
- Using the sample of 30 adults, what would the 95% confidence interval be for the population mean?
- What are the null and alternative hypotheses?
- What is the critical value at 95% confidence?
- Calculate the test statistic.
- Find the p-value
- What conclusion would be made here at the 95% confidence level?
- Would my conclusion change if I changed alpha to .01? Show reasoning

Answer #1

It is known that the average tuition per semester at colleges
in Virginia is $3712. Suppose we take a sample of 15 colleges and
find that the average tuition per semester is $4512 with a sample
standard deviation of $595. We are interested in testing if the
average amount of tuition is increasing.
Using the sample of 15 people, what would the 95% confidence
interval be for the population mean?
What are the null and alternative hypotheses?
What is the...

It is known that the average tuition per semester at colleges
in Virginia is $3712. Suppose we take a sample of 15 colleges and
find that the average tuition per semester is $4512 with a sample
standard deviation of $595. We are interested in testing if the
average amount of tuition is increasing. Show work and formulas
used.
Using the sample of 15 people, what would the 95% confidence
interval be for the population mean?
What are the null and...

3. The average pulse rate is known to be 80 beats per minutes.
Suppose we take a sample of 30 adults and find that the average
heart rate in the sample is 73.76 with a sample standard deviation
of 7.06. We are interested in testing if the average pulse rate is
actually lower than 80 beats per minute. ( please show all steps
and how you got each number)
a. Using the sample of 30 adults, what would the 95%...

In a study of the accuracy of fast food drive-through orders,
Restaurant A had 241 accurate orders and 70 that were not accurate.
a. Construct a 95% confidence interval estimate of the percentage
of orders that are not accurate. b. Compare the results from part
(a) to this 95% confidence interval for the percentage of orders
that are not accurate at Restaurant B: 0.208less thanpless
than0.297. What do you conclude?
a. Construct a 95% confidence interval. Express the percentages
in...

A random sample of 49 lunch customers was selected at a
restaurant. The average amount of time the customers in the sample
stayed in the restaurant was 40 minutes. From past experience, it
is known that the population standard deviation equals 10
minutes.
a.
Compute the standard error of the mean.
b.
Construct a 95% confidence interval for the true
average amount of time customers spent in the restaurant.
c.
With a .95 probability, what sample size would have to...

(solve manually) a randomn sample of 49 lunch customers was
taken at a restaurant. The average amount of time the customers in
the sample stayed in the restaurant was 45 minutes with a standard
deviation of 14 minutes.
a) Construct a 95% confidence interval for the true average
amount of time customers spent in the restaurant.
b) with a .95 probability, how large of a sample would have to
be taken to provide a margin of error of 2.5 minutes...

7. You wish to test the conventional wisdom that the average age
of an American voter is 49. You randomly select n = 36 voters, and
find a sample mean of 53 with a sample standard deviation of
12.
a. Conduct a two-tailed hypothesis test using significance level
? = .05. Clearly state the hypotheses, the test statistic, the
p-value, and your conclusion.
b. Construct a 95% confidence interval, and explain how the
confidence interval confirms your results from part...

John Pizza Restaurant is facing a stiff competition from the new
competing pizza
restaurant guaranteeing pizza deliveries within 32 minutes or
the pizza is given free. To
answer this challenge, Maldini wants to offer a 30-minute
delivery guarantee. After a
careful cost analysis, Maldini has determined that such a
guarantee would require an
average delivery time of less than 27 minutes. She thought that
this would limit the
percentage of ‘free pizzas’ under the guarantee to less than 8%
of...

A random sample found that tourists in Chicago spent an average
of $2860 per week, with a standard deviation of $126. A separate
random sample found that tourists in Miami spent an average of
$2935 per week, with a standard deviation of $138.
The sample sizes are 89 for Chicago and 64 for Miami. Suppose
that you want to find out if there is any
difference between the average expenditures of all of the
tourists who visit the two cities....

Suppose Jason read an article stating that in a 2003‑2004
survey, the average American adult age 19‑30 drank an average of
1.47 liters of plain water per day with a standard deviation of
0.09 liters. Jason wants to find out if the men at his college
drink a similar amount per day. He asks a random sample of 45 male
students in his college to record the amount of water they drink in
one day, and he is willing to...

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