Question
The following gives information about the proportion of a sample that agree with a certain statement....
The following gives information about the proportion of a sample that agree with a certain statement. Use StatKey or other technology to find a confidence interval at the given confidence level for the proportion of the population to agree, using percentiles from a bootstrap distribution. StatKey tip: Use "CI for Single Proportion" and then "Edit Data" to enter the sample information. Find a confidence interval if, in a random sample of 1000 people, 382 agree, 578 disagree, and 40 can't decide.
Click here to access StatKey.
Round your answers to three decimal places.
The 99% confidence interval is Enter your answer to
Use technology to construct the bootstrap distribution, find the appropriate percentiles, and estimate the corresponding proportions.
Homework Answers
Answer #1
Sol:
99% confidence interval for true population proportion who agree is
p^-z*sqrt(p^(1-p^)/n,p^+z*sqrt(p^(1-p^)/n
p^=382/1000=0.382
z alpha/2 for 99%=2.576
99% confidence interval for true population proportion who agree is
0.382-2.576*sqrt(0.382*(1-0.382)/1000,0.382+2.576*sqrt(0.382*(1-0.382)/1000
0.342,0.422
lower limit=0.342
upper limit=0.422
using bootsrap from statkey
99% confidence interval for 100 samples is
0.350,0.415
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