I have a question, which I cannot find the correct solution to from my book.
- Your school Ping-Pong team is not performing very well this
season. After some rough calculations, you found out that your
team's probability of winning a game is about 0.45. A fellow team
member want to know more and asked you also to determine the
following.
a) The probability of the team winning 2 games out of 5
b) The probability of winning 10 times out of 25
Thank you so much in advance! I have answered the question
myself, but would like to compare to someone else's answer to be
sure that I am thinking correctly.
All the best,
Naomi
p = 0.45, q = 1 - p = 0.55
The binomial probability formula is P(x) = C(n, x) p^x q^(n - x)
(a) n = 5, x = 2
x | P(x) = C(5, x) 0.45^x 0.55^(5 - x) |
0 | 0.0503 |
1 | 0.2059 |
2 | 0.3369 |
3 | 0.2757 |
4 | 0.1128 |
5 | 0.0185 |
P(2) = 0.3369
(b) n = 25, x = 10
x | P(x) = C(25, x) 0.45^x 0.55^(25 - x) |
0 | 0.0000 |
1 | 0.0000 |
2 | 0.0001 |
3 | 0.0004 |
4 | 0.0018 |
5 | 0.0063 |
6 | 0.0172 |
7 | 0.0381 |
8 | 0.0701 |
9 | 0.1084 |
10 | 0.1419 |
11 | 0.1583 |
12 | 0.1511 |
13 | 0.1236 |
14 | 0.0867 |
15 | 0.0520 |
16 | 0.0266 |
17 | 0.0115 |
18 | 0.0042 |
19 | 0.0013 |
20 | 0.0003 |
21 | 0.0001 |
22 | 0.0000 |
23 | 0.0000 |
24 | 0.0000 |
25 | 0.0000 |
P(10) = 0.1419
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