Question

What is the probability of being dealt exactly 1 pair (x,x,y,z,w) in a poker hand?

What is the probability of being dealt exactly 1 pair (x,x,y,z,w) in a poker hand?

Math   Statistics-And-Probability   
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Homework Answers

Answer #1

total number of selecting 5 card out of 52 cards = 52C5

hence

required probability = (13*6 * 12*11*10/6 * 64)/(52*51*50*49*48/120)

= 0.42256

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