Question

If nequals400 and Xequals80​, construct a 95​% confidence interval estimate of the population proportion. nothingless than...

If nequals400 and Xequals80​, construct a 95​% confidence interval estimate of the population proportion. nothingless than or equalspiless than or equals nothing ​(Round to four decimal places as​ needed.)

Homework Answers

Answer #1

Given that, n = 499 and x = 80

=> sample proportion = 80/400 = 0.2

A 95% confidence level has significance level of 0.05 and critical value is,

The 95% confidence interval estimate of the population proportion is,

ANSWER : 0.1608 ≤ p ≤ 0.2392

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Use the sample data and confidence level to construct the confidence interval estimate of the population...
Use the sample data and confidence level to construct the confidence interval estimate of the population proportion p. n equals 600 comma x equals 120 comma 90 % confidence nothingless than p less than nothing ​(Round to three decimal places as​ needed.)
Construct a 95​% confidence interval to estimate the population proportion with a sample proportion equal to...
Construct a 95​% confidence interval to estimate the population proportion with a sample proportion equal to 0.60 and a sample size equal to 450. LOADING... Click the icon to view a portion of the Cumulative Probabilities for the Standard Normal Distribution table. A 95​% confidence interval estimates that the population proportion is between a lower limit of nothing and an upper limit of nothing.
If n equals=200 and X equals=70construct a 99%confidence interval estimate for the population proportion nothingless than...
If n equals=200 and X equals=70construct a 99%confidence interval estimate for the population proportion nothingless than or equals≤piπless than or equals≤nothing
Construct a 95​% confidence interval to estimate the population mean when x=122 and s =28 for...
Construct a 95​% confidence interval to estimate the population mean when x=122 and s =28 for the sample sizes below. ​a) n=30       ​b) n=70       ​c) n=90 a) The 95​% confidence interval for the population mean when n=30 is from a lower limit of to an upper limit of. ​(Round to two decimal places as​ needed.) ​b) The 95​% confidence interval for the population mean when n=70 is from a lower limit of to an upper limit of . ​(Round to...
24,19,21,20,18,19,16,17,21,20,18,16,21,17,19,17,17,16,16,19,15,23 a. Construct a 9999​% confidence interval estimate for the population mean miles per gallon of...
24,19,21,20,18,19,16,17,21,20,18,16,21,17,19,17,17,16,16,19,15,23 a. Construct a 9999​% confidence interval estimate for the population mean miles per gallon of 2008 SUVs priced under​ $30,000, assuming a normal distribution. nothing less than or equals≤muμless than or equals≤nothing ​(Round to two decimal places as​ needed.)
1.)If n=400 and X=100​, construct a 95​% confidence interval estimate of the population proportion. ≤π≤ (ROUND...
1.)If n=400 and X=100​, construct a 95​% confidence interval estimate of the population proportion. ≤π≤ (ROUND 4 DECIMAL PLACES) 2.) 19A telecommunications company wants to estimate the proportion of households that would purchase an additional telephone line if it were made available at a substantially reduced installation cost. Data are collected from a random sample of 500 households. The results indicate that 120 of the households would purchase the additional telephone line at a reduced installation cost. a. Construct a...
Construct a 90​% confidence interval of the population proportion using the given information. x equals 240...
Construct a 90​% confidence interval of the population proportion using the given information. x equals 240 comma n equals 300 The lower bound is nothing. The upper bound is nothing. ​(Round to three decimal places as​ needed.)
In a survey of 809 human resource professionals concerning challenges they faced in the​ workplace, 328...
In a survey of 809 human resource professionals concerning challenges they faced in the​ workplace, 328 said that employee​ retention/turnover was an important challenge and 191 said that employee satisfaction was an important challenge. Complete parts​ (a) through​ (c) below. a. Construct a​ 95% confidence interval estimate of the population proportion of human resource professionals who believe that employee​ retention/turnover was an important challenge. The​ 95% confidence interval estimate for the population proportion is nothingless than or equalspiless than or...
Determine the margin of error for a 95% confidence interval to estimate the population mean when...
Determine the margin of error for a 95% confidence interval to estimate the population mean when s​ = 37 for the sample sizes below. ​a) nequals=15 ​b) nequals=34 ​c) nequals=46 ​a) The margin of error for a 95​% confidence interval when nequals=15 is nothing. ​(Round to two decimal places as​ needed.) ​b) The margin of error for a 95% confidence interval when nequals=34 is nothing. ​(Round to two decimal places as​ needed.) ​c) The margin of error for a 95​%...
Construct a confidence interval of the population proportion at the given level of confidence. x=540, n=1100​,...
Construct a confidence interval of the population proportion at the given level of confidence. x=540, n=1100​, 95​% confidence The lower bound of the confidence interval is _______. ​(Round to three decimal places as​ needed.) The upper bound of the confidence interval is_______. ​(Round to three decimal places as​ needed.)
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT