Question

(a) Present the regression output below noting the coefficients, assessing the adequacy of the model and...

(a) Present the regression output below noting the coefficients, assessing the adequacy of the model and the p-value of the model and the coefficients individually.

SUMMARY OUTPUT
Regression Statistics
Multiple R 0.19476248
R Square 0.037932424
Adjusted R Square 0.035147858
Standard Error 12.09940236
Observations 694
ANOVA
df SS MS F Significance F
Regression 2 3988.511973 1994.255986 13.62238235 1.5759E-06
Residual 691 101159.3165 146.3955376
Total 693 105147.8284
Coefficients Standard Error t Stat P-value Lower 95% Upper 95% Lower 95.0% Upper 95.0%
Intercept 27.88762549 0.747028382 37.33141358 7.6561E-168 26.42090772 29.35434326 26.42090772 29.35434326
Gender -1.45054741 0.924086858 -1.569708948 0.116940613 -3.264902321 0.363807502 -3.264902321 0.363807502
Degree Type 4.662178098 0.975135895 4.781054748 2.13194E-06 2.747593355 6.576762841 2.747593355 6.576762841

Homework Answers

Answer #1

Present the regression output below noting the coefficients, assessing the adequacy of the model and the p-value of the model and the coefficients individually.

since the p-value=1.5759E-06 of F of the regression is less than typical level of significance alpha=0.05, so we reject the null hypothesis that all the regression coefficients are zero and conclude that atleast one regression coefficeint is non-zero. since the R-square is 0.0379, which is very low, so taking consideration of this R-square we can say overall this model is not good.

we we go for individual regression coefficient,

p-value=0.0.1169 for Gender, so it is not significant and p-value=2.13194E-06 for Degree type is significant at alpha=0.05, so it can Gender can be remove from the model and reanalyze the data.

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