Assume a Poisson distribution. a. If lambda=2.5, find P(X=5). b. If lambda=8.0, find P(X=10). c. If lambda=0.5, find P(X=0). d. If lambda=3.7, find P(X=4). ROUND TO FOUR DECIMAL PLACES AS NEEDED
Solution :
Given that ,
mean = = = 2.5
Using Poisson probability formula,
P(X = x) = (e- * x ) / x!
a)
P(X = 5) = (e-2.5 * 2.55) / 5!
= 0.0668
Probability = 0.0668
b)
mean = = = 8
P(X = 10) = (e-8 * 810) / 10!
= 0.0993
Probability = 0.0993
c
mean = = = 0.5
P(X = 0) = (e-0.5 * 0.50) / 0!
= 0.6065
Probability = 0.6065
d)
mean = = = 3.7
P(X = 4) = (e-3.7 * 3.74) / 4!
= 0.1931
Probability = 0.1931
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