Question

With 90 percent confidence, for sample mean 342.50, sample standard deviation 12.60, and sample size 35, what is the upper confidence limit with 2 decimal places?

Answer #1

Solution :

Given that,

= 342.50

s = 12.60

n = 35

Degrees of freedom = df = n - 1 = 35 - 1 = 34

At 90% confidence level the t is ,

= 1 - 90% = 1 - 0.90 = 0.1

= 0.1

t_{
,df} = t_{0.1,34} =1.307 (from table)

Margin of error = E = t_{,df}
* (s /n)

= 1.307 * (12.60 / 35) = 2.78

The 90% upper confidence limit is

+ E

342.50 + 2.78

345.28

upper confidence limit 345.28

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