If, in a sample of nequals20 selected from a normal
population, Upper X overbar equals 57 and Upper S equals 12, what
is your statistical decision if the level of significance, alpha,
is 0.05, the null hypothesis, Upper H 0, is mu equals 50 comma
and the alternative hypothesis, Upper H 1 comma is mu not equals
50 question mark
Click here to view page 1 of the table of the critical values of
t.LOADING... Click here to view page 2 of the table of the critical
values of t.LOADING...
Determine the critical value(s).
The critical value(s) is(are)
nothing.
(Round to four decimal places as needed. Use a comma to separate
answers as needed.)
Determine the test statistic tSTAT (Round to four decimal places as needed)
Solution,
The null and alternative hypothesis is ,
H0 : = 50
Ha : 50
= 57
s = 12
n = 20
degrees of frredom = n - 1 = 20 - 1 = 19
This is the two tailed test
= 0.05
/2
= 0.025
t/2,df
= t0.025,19 = 2.0930
critical value = -2.0930, 2.0930
Test statistic = t =
= ( - ) / s / n
= (57 - 50) / 12 / 20
Test statistic = t = 2.6087
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