Question

Given the sample mean = 22.325, sample standard deviation = 5.8239, and N = 40 for...

Given the sample mean = 22.325, sample standard deviation = 5.8239, and N = 40 for the low income group,

Test the claim that the mean nickel diameter drawn by children in the low income group is greater than 21.21 mm. Test at the 0.01 significance level.

a) Identify the correct alternative hypothesis:

  • μ>21.21μ>21.21
  • p<21.21p<21.21
  • p=21.21p=21.21
  • μ<21.21μ<21.21
  • p>21.21p>21.21
  • μ=21.21μ=21.21



Give all answers correct to 3 decimal places.

b) The test statistic value is:     

c) Using the Traditional method, the critical value is:  

d) Based on this, we

  • Reject H0H0
  • Fail to reject H0H0



e) Which means

  • The sample data supports the claim
  • There is not sufficient evidence to warrant rejection of the claim
  • There is sufficient evidence to warrant rejection of the claim
  • There is not sufficient evidence to support the claim

Homework Answers

Answer #1

This is the right tailed test .

The null and alternative hypothesis is

H0 : = 21.21

Ha : > 21.21

Test statistic = t

= ( - ) / s / n

= (22.325 - 21.21) / 5.8239 / 40

Test statistic = 1.210

Critical value = 2.426

Fail to reject H0

There is not sufficient evidence to warrant rejection of the claim

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