12 dollars.
Question 1. How large a sample should she take to estimate the mean amount spent to within 2 dollars with 99% confidence? (Round your answer up to the next largest integer).
Solution :
Given that,
standard deviation = =$12
Margin of error = E = $2
At 99% confidence level the z is,
= 1 - 99%
= 1 - 0.99 = 0.01
/2 = 0.005
Z/2 = 2.58 ( Using z table ( see the 0.005 value in standard normal (z) table corresponding z value is 2.58 )
sample size = n = [Z/2* / E] 2
n = ( 2.58* 12 / 2 )2
n =239.63
Sample size = n =240
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