How many subjects need to be sampled if we are estimating the population proportion and we want a 90% confidence level with the error of at most 2 percentage points?
Solution :
Given that,
= 0.5
1 - = 0.5
margin of error = E = 2% = 0.02
At 90% confidence level
= 1 - 90%
= 1 - 0.90 =0.10
/2
= 0.05
Z/2
= Z0.05 = 1.645 ( Using z table )
Sample size = n = (Z/2 / E)2 * * (1 - )
= (1.645 / 0.02)2 * 0.5 * 0.5
=1691.26
Sample size = 1691
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