Question

Suppose a farmer would like to try three different types of fertilizers to see if the crop yield increases. Using a .05 level of significance, test to see if there is a difference in the fertilizers.

Fertilizer

A          B          C         

12         20         16

13         22         14

15         19         18

19         25         18                    

Totals 59         86         66         211                  

Answer 1

Using Excel

data -> data analysis -> ANOVA single Factor

p-value = 0.0132 < alpha(0.05)

hence we reject the null hypothesis

we conclude that there is significant difference in the fertilizers.

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