Question

Suppose a farmer would like to try three different types of fertilizers to see if the crop yield increases. Using a .05 level of significance, test to see if there is a difference in the fertilizers.

**Fertilizer**

**A
B C
**

12 20 16

13 22 14

15 19 18

19 25 18

**Totals
59
86
66
211
**

Answer #1

Using Excel

data -> data analysis -> ANOVA single Factor

p-value = 0.0132 < alpha(0.05)

hence we reject the null hypothesis

we conclude that there is significant difference in the fertilizers.

Please give me a thumbs-up if this helps you out. Thank you!
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Suppose a farmer would like to try three different types of
fertilizers to see if the crop yield increases and he tests the
fertilizer on four different plots of land.
Fertilizer
Plot
Of
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12
20
16
48
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