The following data represent crime rates per 1000 population for a random sample of 46 Denver neighborhoods.
63.2 | 36.3 | 26.2 | 53.2 | 65.3 | 32.0 | 65.0 |
66.3 | 68.9 | 35.2 | 25.1 | 32.5 | 54.0 | 42.4 |
77.5 | 123.2 | 66.3 | 92.7 | 56.9 | 77.1 | 27.5 |
69.2 | 73.8 | 71.5 | 58.5 | 67.2 | 78.6 | 33.2 |
74.9 | 45.1 | 132.1 | 104.7 | 63.2 | 59.6 | 75.7 |
39.2 | 69.9 | 87.5 | 56.0 | 154.2 | 85.5 | 77.5 |
84.7 | 24.2 | 37.5 | 41.1 |
(a) Use a calculator with mean and sample standard deviation keys to find the sample mean x and sample standard deviation s. (Round your answers to one decimal place.)
x = | crimes per 1000 people |
s = | crimes per 1000 people |
(b) Let us say the preceding data are representative of the
population crime rates in Denver neighborhoods. Compute an 80%
confidence interval for μ, the population mean crime rate for all
Denver neighborhoods. (Round your answers to one decimal
place.)
lower limit | crimes per 1000 people |
upper limit | crimes per 1000 people |
(c) Compute a 95% confidence interval for μ, the population mean crime rate for all Denver neighborhoods. (Round your answers to one decimal place.)
lower limit | crimes per 1000 people |
upper limit | crimes per 1000 people |
The statistical software output for this problem is :
(a)
x = 64.2
s = 27.9
(b)
Lower limit = 58.8
Upper limit = 69.5
(c)
Lower limit = 55.9
Upper limit = 72.4
Get Answers For Free
Most questions answered within 1 hours.