Assume that the significance level is alpha equals 0.1. Use the given statement and find the P-value and critical value(s). The test statistic of z=-1.56 is obtained when testing the claim that p=1/5.
Can someone explain how to do this on TI-84 calculator?
The Normal Probability Distribution menu for the TI-83+/84+ is found under DISTR (2nd VARS). NOTE: A mean of zero and a standard deviation of one are considered to be the default values for a normal distribution on the calculator, if you choose not to set these values. |
p-value = 2 P(z >|TS|) = 2 P(Z > 1.56)
= 0.1188
= 1- P(-1.56 < Z < 1.56)
use normalcdf ((-1.56,1.56,0,1)
critical values are
P(-z < Z < z) = 0.9
P(Z <z) = (1- (1-0.9)/2) = 0.95
z = 1.645
use invNorm( 0.95)
Get Answers For Free
Most questions answered within 1 hours.