GMAT scores for students accepted to Suffolk University’s MBA program are approximately normally distributed with a mean score of 465 and a standard deviation of 103.
a. What score does a student need to have to be at the 85th percentile? Do not round.
b. What is the probability that an accepted student has a GMAT score between 400 and 500? Round z-values to 2 decimal places.
Given that,
mean = = 465
standard deviation = = 103
Using standard normal table,
P(Z < z) =85 %
= P(Z < z) = 0.85
= P(Z <1.04 ) = 0.85
z =1.04 Using standard normal z table,
Using z-score formula
x= z * +
x= 1.04 *103+465
x= 572.12
(B)
P(400< x <500 ) = P[(400-465) /103 < (x - ) / < (500-465) /103 )]
= P( -0.63< Z <0.34 )
= P(Z <0.34 ) - P(Z < -0.63)
Using z table
= 0.6331-0.2643
probability= 0.3688
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