A hospital administrator finds that the mean hospital stay for a sample of
86
women after childbirth is
2.9
days. She claims that the mean stay at her hospital is greater than the national average of
2.4
days. Assuming that the average at her hospital is the same as the national average, the probability of observing a sample with a mean of
2.9
days or more is
0.17
Formulate the null and alternative hypotheses. Then discuss whether the sample provides evidence for rejecting or not rejecting the null hypothesis. Assume a significance level of
0.05
Identify the hypotheses.
A.Null hypothesis: mean
stayequals=2.4
daysAlternative hypothesis: mean
stayequals=2.9
days
B.Null hypothesis: mean
stayequals=2.4
daysAlternative hypothesis: mean
stayless than<2.4
days
C.Null hypothesis: mean
stayequals=2.4
daysAlternative hypothesis: mean
staygreater than>2.4
days
D.Null hypothesis: mean
stayequals=2.4
daysAlternative hypothesis: mean
staynot equals≠2.4
daysIs the result of the test statistically significant at the
0.05
level?
A.The test
is not
statistically significant at the
0.050.05
level, because the chance of a sample mean at least as extreme as the observed one is
greater
than
0.05,
assuming the null hypothesis to be true.
B.The test
is not
statistically significant at the
0.05
level, because the chance of a sample mean at least as extreme as the observed one is
less
than
0.05,
assuming the null hypothesis to be true.
C.The test
is
statistically significant at the
0.05
level, because the chance of a sample mean at least as extreme as the observed one is
less
than
0.05,
assuming the null hypothesis to be true.
D.The test
is
statistically significant at the
0.05
level, because the chance of a sample mean at least as extreme as the observed one is
greater
than
0.05,
assuming the null hypothesis to be true.
Determine if the null hypothesis should be rejected.
A.
Do not reject
the null hypothesis because the chance of the sample result is
greater
than the significance level.
B.
Do not reject
the null hypothesis because the chance of the sample result is
less
than the significance level.
C.
Reject
the null hypothesis because the chance of the sample result is
greater
than the significance level.
D.
Reject
the null hypothesis because the chance of the sample result is
less
than the significance level.
We want to test the claim that the mean stay is greater than 2.4
Therefore, the hypothesis to tested will be,
Null hypothesis: Mean stay = 2.4
Alternative hypothesis: Mean stay > 2.4 (claim)
Option C
Now, the p value i.e. the probability of observing sample mean >= 2.9 is 0.17, under null hypothesis.
Since, 0.17>0.05, we do not reject null hypothesis. The claim proves to be false/insignificant.
Therefore, the correct option is Option A
And also because we are not rejecting the null hypothesis because Pvalue is greater than significance level(0.05) the correct option is Option A
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