Suppose the weights of Farmer Carl's potatoes are normally distributed with a mean of 7.9 ounces and a standard deviation of 1.1 ounces.
(a) If 5 potatoes are randomly selected, find the probability
that the mean weight is less than 9.5 ounces.
Round your answer to 4 decimal places.
(b) If 6 potatoes are randomly selected, find the probability that
the mean weight is more than 8.9 ounces.
Round your answer to 4 decimal places.
Solution :
Given that ,
mean = = 7.9
standard deviation = = 1.1
n = 5
= 7.9
= / n = 1.1/ 5=0.4919
P( <9.5 ) = P[( - ) / < (9.5-7.9) / 0.4919]
= P(z <3.25 )
Using z table
= 0.9994
probability= 0.9994
(B)
n = 6
= 7.9
= / n = 1.1/ 6 = 0.4491
P( >8.9 ) = 1 - P( <8.9)
= 1 - P[( - ) / < (8.9 -7.9) / 0.4491]
= 1 - P(z <2.23)
Using z table
= 1 - 0.9871
= 0.0129
probability= 0.0129
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