let X represent the number of occupants in a randomly chosen car on a certain stretch of highway during morning commute hours. A survey of cars showed that the probability distribution of
X is as follows.
x |
1 |
2 |
3 |
4 |
5 |
---|---|---|---|---|---|
Px |
0.66 |
0.11 |
0.08 |
0.02 |
0.13 |
Compute the standard deviation
σX. Round the answer to three decimal places.
Solution:
x | P(x) | x * P(x) | x2 * P(x) |
1 | 0.66 | 0.66 | 0.66 |
2 | 0.11 | 0.22 | 0.44 |
3 | 0.08 | 0.24 | 0.72 |
4 | 0.02 | 0.08 | 0.32 |
5 | 0.13 | 0.65 | 3.25 |
Sum | 1 | 1.85 | 5.39 |
Solution :
Mean = X * P(X)
= 1.85
Standard deviation =
=X 2 * P(X) - 2
= 5.39 - (1.85)2 = 1.9675
Standard deviation = = 1.403
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