Question

1. Calculate the mean and standard deviation for the numbers 1 – 20. ​i.e.) 1, 2,...

1. Calculate the mean and standard deviation for the numbers 1 – 20.

​i.e.) 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20

​Note: The set of numbers will be considered the population.

​µ = _______​​​σ = ________

2. With your calculator, randomly generate 5 numbers from the numbers 1 – 20, 30 times.

​Use:​[MATH]>>>PRB #5

​​RandInt(1,20,5)​[ENTER]​​Note: You cannothave the same number repeated in the group of 5.

​​​​​​For example: You cannot have {2,2,10,13,8} where the 2 is repeated.

After you generate your first 5 numbers, write them down in the space below, then hit [ENTER] again to generate

  another 5 numbers. When you finish, you should have 30 groups of 5numbers ranging from 1 – 20.  

3. Calculate the mean for each of the 30 groups and write them in the space below. You should have 30 sample means

when you finish.

4. Calculate the mean and standard deviation for the 30 sample means. Place your values in the space below and

label your values with the appropriate symbols. Note: Enter your 30 sample means into L1 in your calculator

and do 1-var stat L1 to get the mean and standard deviation.

5.   Using your values from part 1 and part 4, test the 3 properties of the Distribution of Sample Means:

​a.) Write the property for Mean of the Sample Means. Show the values for your means and state whether they

​   approximate the property.

​b.)   Write the property for the Standard Deviation of the Sample Means. Show the values for your standard

​   deviations and state whether they approximate the property.

​c.)   On a piece of graph paper, draw a graph (histogram) to approximate the population, then draw a 2nd

​   histogram to approximate the 30 sample means.  ( Hint: Create a frequency distribution for each set of

​   data – population and sample means – then draw a histogram for each frequency distribution.)

Homework Answers

Answer #1

Answer :

Mean ( ) = 10.5

standard deviation ( ​​​σ ) = 5.7663

Explanation :

( 1 )

  • Mean ( ) = Sum of terms / Number of terms

=  210 / 20

= 10.5

  • standard deviation ( ​​​σ ) :

Create the following table.

So mean = 10.5

data data-mean (data - mean)2
1 -9.5 90.25
2 -8.5 72.25
3 -7.5 56.25
4 -6.5 42.25
5 -5.5 30.25
6 -4.5 20.25
7 -3.5 12.25
8 -2.5 6.25
9 -1.5 2.25
10 -0.5 0.25
11 0.5 0.25
12 1.5 2.25
13 2.5 6.25
14 3.5 12.25
15 4.5 20.25
16 5.5 30.25
17 6.5 42.25
18 7.5 56.25
19 8.5 72.25
20 9.5 90.25

∑(data - mean)2= 665

σ = Sqrt ( ∑(data - mean)2 / n )

= Sqrt ( 665 / 20 )

= Sqrt ( 33 .25 )

= 5.76628130

~ 5.7663 ( approximately)

  

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Calculate the mean and the (sample) standard deviation of the four numbers: 2, 3, 6, 9...
Calculate the mean and the (sample) standard deviation of the four numbers: 2, 3, 6, 9 1 (a) Two numbers, a and b, are to be added to this set of four numbers, such that the mean is increased by 1 and the (sample) standard deviation is increased by 2.5. Find the values of a and b. I want to the values of a and b
A distribution of values is normal with a mean of 130 and a standard deviation of...
A distribution of values is normal with a mean of 130 and a standard deviation of 27. From this distribution, you are drawing samples of size 31. Find the interval containing the middle-most 84% of sample means: Enter your answer using interval notation in the form (a,b). In this context, either inclusive or exclusive intervals would be acceptable. Your numbers should be accurate to 1 decimal places. Answers obtained using z-scores rounded to 2 decimal places are accepted.
1. A distribution of values is normal with a mean of 110.8 and a standard deviation...
1. A distribution of values is normal with a mean of 110.8 and a standard deviation of 33.5. Find the probability that a randomly selected value is less than 20.7. P(X < 20.7) = Enter your answer as a number accurate to 4 decimal places. *Note: all z-scores must be rounded to the nearest hundredth. 2. A distribution of values is normal with a mean of 2368.9 and a standard deviation of 39.4. Find the probability that a randomly selected...
A distribution of values is normal with a mean of 80 and a standard deviation of...
A distribution of values is normal with a mean of 80 and a standard deviation of 22. From this distribution, you are drawing samples of size 34. Find the interval containing the middle-most 36% of sample means: Enter answer using interval notation. In this context, either inclusive or exclusive intervals would be acceptable. Your numbers should be accurate to 1 decimal places. Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted.
Suppose a variable has a normal distribution with mean 12 and standard deviation 2. Use the...
Suppose a variable has a normal distribution with mean 12 and standard deviation 2. Use the Empirical Rule to calculate the approximate PERCENTAGE area. What is the PERCENTAGE of values ABOVE 10? Note: Enter X.XX AT LEAST ONE DIGIT BEFORE THE DECIMAL, TWO AFTER and round up. Thus, 7 is entered as 7.00, 3.5 is entered as 3.50, 0.3750 is entered as 0.38 |Enter PERCENTAGE in above blank with NO % sign. | Suppose a variable has a normal distribution...
Suppose we repeatedly take samples of size 100 from the population distribution, calculate a sample mean...
Suppose we repeatedly take samples of size 100 from the population distribution, calculate a sample mean each time, and plot those sample means in a histogram. The histogram we created would be an example of a (variable, population, distribution, sampling distribution???) . According to the central limit theorem, the histogram would have a shape that is approximately (left skewed, right skewed or normal???) , with mean  (give a number???) and standard deviation  (give a number??). The standard deviation of the statistic under...
1. For a standard normal distribution, given: P(z < c) = 0.9353 Find c. 2. A...
1. For a standard normal distribution, given: P(z < c) = 0.9353 Find c. 2. A population of values has a normal distribution with μ=195.6μ=195.6 and σ=42.9σ=42.9. You intend to draw a random sample of size n=203n=203. What is the mean of the distribution of sample means? μ¯x=μx¯= What is the standard deviation of the distribution of sample means? (Report answer accurate to 2 decimal places.) σ¯x=σx¯= 3.A population of values has a normal distribution with μ=5.8μ=5.8 and σ=80σ=80. You...
A population of values has a normal distribution with mean of 50.3 and standard deviation of...
A population of values has a normal distribution with mean of 50.3 and standard deviation of 84.   Find the probability that from a sample of 226 the sample mean is greater than 49.7. Enter your answers as numbers accurate to 4 decimal places.
Suppose x has a distribution with a mean of 90 and a standard deviation of 20....
Suppose x has a distribution with a mean of 90 and a standard deviation of 20. Random samples of size n = 64 are drawn. (a) Describe the distribution. has an approximately normal distribution. has a normal distribution. has a geometric distribution. has a binomial distribution. has an unknown distribution. has a Poisson distribution. Compute the mean and standard deviation of the distribution. (For each answer, enter a number.) = mu sub x bar = = sigma sub x bar...
1. The mean score on the ACT test was 21.7 and the standard deviation was 5.2...
1. The mean score on the ACT test was 21.7 and the standard deviation was 5.2 . The distributions of scores was approximately bell-shaped. Compute the z-score for an ACT test score of 17 . Write only a number as your answer. Round your answer to two decimal places (for example: 3.15). 2. A population has mean 25 and standard deviation 17 . What is the data value that has a z-score of 1 ? Write only a number as...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT